mirror of
https://github.com/MillironX/beefblup.git
synced 2024-11-14 03:23:09 +00:00
Terminate if there are more contemporary groups than animals
This commit is contained in:
parent
b372608f2e
commit
6743790804
2 changed files with 48 additions and 29 deletions
|
@ -33,6 +33,8 @@ animalrow = @(id) find(ids == id);
|
|||
numanimals = length(ids);
|
||||
|
||||
% Store column numbers that need to be deleted
|
||||
% Column 6 contains an intermediate Excel calculation and always needs to
|
||||
% be deleted
|
||||
colstodelete = 6;
|
||||
|
||||
% Coerce each group to string format
|
||||
|
@ -48,3 +50,20 @@ for i = 7:length(headers)
|
|||
colstodelete = [colstodelete i];
|
||||
end
|
||||
end
|
||||
|
||||
% Delete the appropriate columns from the datasheet and the headers
|
||||
data(:,colstodelete) = [];
|
||||
headers(colstodelete) = [];
|
||||
|
||||
% Determine how many contemporary groups there are
|
||||
numgroups = ones(1, length(headers)-5);
|
||||
for i = 6:length(headers)
|
||||
numgroups(i) = length(unique(data(:,i)));
|
||||
end
|
||||
|
||||
% If there are more groups than animals, then the analysis cannot continue
|
||||
if sum(numgroups) >= numanimals
|
||||
disp('There are more contemporary groups than animals. The analysis will now abort.');
|
||||
return
|
||||
end
|
||||
|
||||
|
|
Loading…
Reference in a new issue