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Removing debugging print line from parameter parsing function
Signed-off-by: Thomas A. Christensen II <25492070+MillironX@users.noreply.github.com>
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@ -38,7 +38,6 @@ def params_to_list(params):
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tuple_item += tuple_list
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return tuple_item
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else:
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print(params)
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io_item = nodes.list_item()
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if "name" in params.keys():
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io_item += nodes.paragraph(text=params["name"])
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